Question

Find the refractive index of a liquid which the critical angle is 60 degree

Answer 1

Answer:

1.15 [apprx.]

Explanation:

Refractive index; n = $\frac{1}{sinc}$

where, c = critical angle of medium

Given,

c = 60°

So,

sin c = sin 60°

=> sin c = $\frac{\sqrt{3} }{2}$

=> $\frac{1}{sinc}$ = $\frac{2}{\sqrt{3} }$

=> n = $\frac{2}{\sqrt{3} }$ = $\frac{2}{1.732}$

=> n = 1.15 [apprx]