Question

Find the refractive index of core, given the refractive index of cladding is 1.1882, the NA is 0.3 and the relative index difference is 3%.

a. 1.2249
b. 1.3249
c. 1.4249
d. 1.4349​

Answer 1

Answer:

μ

2

sin(90°−r)=μ

1

×sin90°

∴cosr=

μ

2

μ

1

Snell's law at first refraction gives,

1×sini=μ

2

×sinr

∴sini=μ

2

×

1−cos

2

r

=μ

2

1−(

μ

2

μ

1

)

2

sini=

μ

2

2

−μ

1

2

i=sin

−1

μ

2

2

−μ 1

2

please mark as brainlist