Question

Find the relatice population of the two states in a ruby laser that produce a light of wacelength 6943 at 300k

Answer 1

The relative population of two states is 7.99*10^(-31).

Maxwell develop a formula for the relative population of two states in a active laser, and its given as

$\frac{N}{N_{o} }$=$e^{\frac{-hc}{λKT} }$

Here, N is the population in the upper state, N_{o} is the population in the ground state

h=6.64*10^(-34) J-s is planck's constant

c=3*10^8 m/s is speed of light

K=1.38*10^(-23) m2 kg s-2 K-1 is the Boltzmann's constant

λ is wavelength of laser light

T is temperature

Plugging the values in the above equation

$\frac{N}{N_{o} }$=$e^{\frac{-6.64*10^(-34)*3*10^8 }{6943^10(-10)*1.38*10^(-23)*300} }$

$\frac{N}{N_{o} }$=7.99*10^(-31)