Math, asked by 7218022778s, 11 months ago

find the relation and zeroes of these polynomials​

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Answers

Answered by haimz
1

3x^2 + 4x - 4

Step-by-step explanation:

3x^2 + 6x - 2x -4

3x {x + 2 } -2 {x + 2 }

{ 3x- 2 } { x+2}

x = 2/3 , -2

5t^2 +12t +7

5t^2 + 5t + 7 t + 7

5t { t +1 } + 1 { t + 1 }

{ 5t +1 } { t+1 }

t = -1/5 , -1

Answered by ferozemulani
1

Step-by-step explanation:

3x^2+4x-4=0

3x^2 + 6x-2x -4=0

3x(x+2) - 2 (x+2)=0

(3x-2)(x+2)=0

x=(2/3) & x=-2

5t^2+12t+7=0

5t^2 + 5t + 7t + 7 =0

5t(t+1) + 7(t+1) =0

(5t+7) (t+1) = 0

t =-(7/5) & t = -1

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