Find the relation between a, b, c, d for which equartions ax+by=c& cx+dy=a have unique solution
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ax+by= c
ax+by- c = 0
cx+dy = a
cx+dy-a = 0
In case of unique solution
a1 = a b1 = b c1 = - c
a2 = c b2 = d c2 = - a
a1/a2# b1/b2 where # stands for not equal
a/c # b/d
ab # cd
Hope it helps
Mark as the BRAINLIEST
ax+by- c = 0
cx+dy = a
cx+dy-a = 0
In case of unique solution
a1 = a b1 = b c1 = - c
a2 = c b2 = d c2 = - a
a1/a2# b1/b2 where # stands for not equal
a/c # b/d
ab # cd
Hope it helps
Mark as the BRAINLIEST
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