Find the relation between a
lation between a, b, a' and b' such that the two lines ax + by= c and a'x + b'y = c' are perpendicular
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Answer:
a a' + b b' = 0
Step-by-step explanation:
Given :
Equation of first line :
a x + b y = c
= > a x + b y - c = 0
Slope of line = - A / B
= > m₁ = - a / b
Equation of second line :
a'x + b'y = c'
= > a'x + b'y - c' = 0
Slope of line = - A / B
= > m₂ = - a' / b'
We know if two line are perpendicular then their slope product is - 1 .
i.e. m₁ m₂ = - 1
Putting values of m₁ and m₂ here :
= > ( - a / b ) ( - a' / b' ) = - 1
= > a a' = - b b'
= > a a' + b b' = 0
Therefore we get required relation.
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