find the relation between l and m
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let side BC be x.
In triangle ABC, using trigonometry -
tan60 = l+m/x = √3 .... equation 1
In triangle EBD -
tan30 = m/x+5 = 1/√3 ... equation 2
dividing equation 1 by equation 2, we get -
(l/m + 1) ( (x+5)/x) = 3
=> l/m = 3x/(x+5) - 1
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