Question

find the relation between p,q and r, if, 49p²+9q²+81r²+21pq-27rq+63rp=0​

Answer 1

Answer:

7p+9z = 3q

Step-by-step explanation:

${7p}^{2} + {3q}^{2} + {9z}^{2} + 3 (7pq \: - 9rq \: + 21rp) = 0$

[°•° (a+b+c)^2 = a^2 + b^2 +c^2 + ab + ac +ab]

${(7p - 3q + 9z)}^{2} = 0$

7p-3q+9z=0

•°• 7p+9z = 3q