Question

find the relation between r and s expansion std9​

Answer 1

Answer:

x+1/x = r

=> x2+1 = rx

=> x2-rx+1 =0

=> x = r+-√r2-4/2

Now, Again, x-1/x = s

=> x2-1= sx

=> x2-sx-1 = 0

=> x = s+-√s2+4/2

So, we get,

r+-√r2-4/2 = s+-√s2+4/2

=> Comparing the rational and irrational parts, we get,

r=s

and, √r2-4 = √s2+4

=> r2-4= s2+4

=> r2-s2 = 8

That's the best I found out. If anything else is there, I don't know.