Math, asked by reddymanojkumar74, 9 months ago

Find the relation between x and y, if (x,y) is equidistant from the points (2,1) and (1,-2).

Answers

Answered by topper05

Answer. Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (3,0)

Answered by guideboy509

@GUIDEBOY

Let the points be P(x,y), A(6,-1) and B(2,3).

AP2 = (x-6)2 + (y+1)2

BP2 = (x-2)2 + (y-3)2

Given, 9(x,y) is equidistant from (6,-1) and (2,3)

(x-6)2 + (y+1)2 = (x-2)2 + (y-3)2

x2 - 12x + 36 + y2 + 2y + 1 = x2 - 4x + 4 + y2 - 6y + 9

-12x + 36 + 2y + 1 = - 4x + 4 - 6y + 9

-8x + 8y = -24

-x + y = -3

x - y = 3.

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