find the relation between x and y in order that the rth mean between x and 2y maybe the same as the rth mean between 2x and y,n means being inserted in each case
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let x, a1, a2, an, 2y be in ap.
then commerce difference =(2y-x)/ (n+1)
ar=x+rd= x+ r (2y-x) / (n+1) =(x(n+1) +r(2y-x)/(n+1)
now 2x,b1,b2, bn,y are in ap.
then common difference = (y-2x)/ (n+1)
br=x+rd =x+r (y-2x)/(n+1) =(x(n+1)+r(y-2x))/(n+1)
since, ar=br, we have:
(x(n+1)+r(2y-x))/(n+1)= (x(n+1)+r(y-2x))/(n+1)
on simplifying, we get,
Ry= x(n-r+1)
this is the required relation.
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