Question

find the relation between x and y such that point P(x,y) is equidistant from A(3,7) B(2,2)




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Answer 1

Question :-

• Find the relation between x and y such that point P(x,y) is equidistant from A(3,7) B(2,2).

Solution :-

Let P(x,y) be equidistant from the points A(3, 7) and B(2, 2).

⟹ AP = BP

⟹ AP² = BP²

⟶ [√(x - 3)² + (y - 7)²]² = [√(x - 2)² + (y - 2)²]²

⟶ (x - 3)² + (y - 7)² = (x - 2)² + (y - 2)²

⟶ x² - 6x + 9 + y² - 14y + 49 = x² - 4x + 4 + y² - 4y + 4

⟶ -6x + 9 - 14y + 49 = -4x + 4 - 4y + 4

⟶ -6x + 58 - 14y = -4x + 8 - 4y

⟶ -6x + 4x = 8 - 4y - 58 + 14y

⟶ -2x = -50 + 10y

Hence Solved !!