Find the relation between x and y such that point x, y is equal distance from the point 36 and - 3, 4
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Step-by-step explanation:
Let the points be a (3,6) and b(-3,4)
And m(x,y)
Given point m is equidistant from a and b
=> ax=bx
=> √(3-x)²+(6-y)²=√(-3-x)²+(4-y)²
=> 9+x²-6x + 36+y²-12y= 9+x²+6x + 16+y²-8y
=>9-9+x²-x² -6x-6x= 16-36-y²+12y+y²-8y
=> -12x = -20 +4y
=> 12x +4y = 20 ( deviding whole by 4
=> 3x+y = 20
= difference between x and y
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