Question

find the relation between X and Y such that the point P X, Y is equidistant
from the point A 7,1 and B 3,5 ​

Answer 1

Step-by-step explanation:

plz mark as BRAINLIAST....

Answer 2

P(x, y) is equidistant from A(7,1) and B(3,5)

So,

√(7-x)²+(1-y)²=√(x-3)²+(y-5)²

(7-x)²+(1-y)² = (x-3)²+(y-5)²

49 + x²-14x+1+y²-2y=x²+9-6x+y²+25-10y

50+x²+y²-14x-2y=34+x²+y²-6x-10y

50-14x-2y=34-6x-10y

16=8x-8y

2=x-y

x=2+y