Question

find the relation between x and y, such that the point (x,y) is equidistant from points (-1,8) and (3,4)

Answer 1

Answer:

∴PA=PB

By using the distance formula

= (x2−x1 )2+(y2 −y1 )2

we have

⇒ (x−3)2+(y−6)2= (x+3) 2+(y−4)2

⇒(x−3)2+(y−6)2=(x+3)2+(y−4)2

⇒x2−6x+9+y 2 −12y+36=x 2+6x+9+y2−8y+16

⇒−6x−6x−12y+8y+36−16=0

⇒−12x−4y+20=0

⇒3x+y−5=0

Hence this is a relation between x and y.

Explanation:

was this answer helpful?

add this as brainly list