Question

Find the relation between x and y such that the point (x,y) is equidistant from the points (3,6) and (-3,4).......​

Answer 1

Answer:

Step-by-step explanation:

We know that (x,y) is equidistant from points (3,6) and (-3,4)

Therefore (x,y) must be the midpoint

So using the formula p(x,y) = (x1 + x2)/ 2 , (y1 + y2) / 2

                                            =   [3 + (-3)]/2 ,  (6 + 4)/2

                                             =    0 , 10/2

                                    p(x,y) = (0, 5)

Hope it helps

Have a great day ;)