Question

find the relation between x and y such that the point x, y is equidistant from the point (4,7) and (4,5)​

Answer 1

Answer:

Step-by-step explanation:

Equidistant means that the point is at equal distance from (4,7) and (4,5)

so by distance formula

$\sqrt{(x-4)^2+{(y-7)^2 } } =\sqrt{(x-4)^2+(y-5)^2}}$

taking square on both sides we get

$(x-4)^2 +(y-7)^2 =(x-4)^2+(y-5)^2$

cancle out (x-4)^2 on both sides

$(y-7)^2=(y-5)^2\\\\y^2+49-14y=y^2+25-10y\\\\-4y=-24\\y=6$