Find the relation between x and y such that the point (x , y) is equidistant from the points (7, 1) and (3 , 5)
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Answer:
the x lies on a same line of 7and 3
as well as y also on a same line of 1 and 5
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Step-by-step explanation:
(x-7)²+(y-1)²=(x-3)²+(y-5)²
x²-14x+49+y²-2y+1=x²+9-6x+y²+25-10y
8x-8y=16
x-y=2
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