Math, asked by lakhanpalmanik, 9 months ago

Find the relation between x and y such that the points (x,y) is equidistant from the points ( 17,-9) and (-3,11).​ NOTE: PLEASE WRITE ANSWER IN NOTEBOOK

Answers

Answered by chhayatrivedi11
1

Step-by-step explanation:

this is example related to it and if you have any doubts about it ask

Attachments:
Answered by hukam0685
1

Step-by-step explanation:

Given:Point (17,-9) (-3,11)

To find:Find the relationship between x and y such that the point P(x,y) is equidistant

Solution:

Distance formula

 \sqrt{( {x_2 - x_1)}^{2}  + ( {y_2 - y_1)}^{2} }  \\  \\

A(17,-9) and B(-3,11)

AP=BP

So,

AP^2=BP^2\\\\ \sqrt{( {17 - x)}^{2}  + ( { - 9 - y)}^{2} }   = \sqrt{( { - 3 - x)}^{2}  + ( { 11 - y)}^{2} }  \\  \\

Square both side

( {17 - x)}^{2}  + ( { - 9 - y)}^{2}    = ( { - 3 - x)}^{2}  + ( { 11 - y)}^{2}  \\  \\ 289 +  {x}^{2}  - 34x + 81 +  {y}^{2}  + 18y = 9 +  {x}^{2}  + 6x + 121 +  {y}^{2}  - 22y \\  \\ cancel \: common \: term \\  \\  - 34x - 6x + 18y + 22y + 289 + 81 - 9 - 121 = 0 \\  \\  - 40x + 40y + 240 = 0 \\  \\  \bold{\pink{- x + y + 60 = 0 }}\\  \\ or \\  \\ \bold{\green{x - y = 60}} \\  \\

So,the relation between x and y is

x-y=60 or -x+y+60=0.

Hope it helps you.

To learn more on brainly:

1)Find a relation between x and y such that the point P(x,y) is equidistant from the points A(7,1) and B(3,5) .

https://brainly.in/question/899765

2)3. Find a relation between x and y such that the point ( x,y) is equidistant from the points (7,1)

and (-1,-4)

https://brainly.in/question/15436893

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