Question

Find the relation between x and y such that (x,y) is equidistant from (7,1) and
(3,5)​

Answer 1

Answer:

x-y=2

let P(x,y) , A(7,1) and B (3,5)

P is equidistant so, AP =BP

By distance formula,

(7-x)²+(1-y)²= (3-x)²+(5-y)²

49-14x+x²+1-2y+y²=9-6x+x²+25-10y+y²

49+1-14x-2y=9+25-6x-10y

50-14x-2y=34-6x-10y

-14x+6x-2y+10y=34-50

-8x+8y=-16

8x-8y=16

x-y=2

Answer 2

Step-by-step explanation:

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