Question

find the relation between x and y that point (x,y) is equidistant from the points (2,7) and (-3,5)​

Answer 1

Answer:

Answer

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP

2

=BP

2

(x−7)

2

+(y−1)

2

=(x−3)

2

+(y−5)

2

x

2

−14x+49+y

2

−2y+1=x

2

−6x+9+y

2

−10y+25

x−y=2

Answer 2

Answer:

sb pg ek u eto y dp all CM xm xm do wp