Question

Find the relation for time period of a simple pendulum
executing S.H.M.
noint mass suspended from a rigid support​

Answer 1

Explanation:

• The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.

Answer 2

Answer:

Section Summary

A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º.

The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.