Question

find the relation independent of y for the equation -2y^2 -2y=p -y^2 +y=q​

Answer 1

Answer:

p² + 4q² - 4pq + 8q - 4p = 0

Step-by-step explanation:

-2y² - 2y = p    Eq1

-y² + y  = q       Eq2

2 * Eq2 - Eq1

=> 2y - (-2y) = 2q - p

=> 4y = 2q - p

=>  y = (2q - p)/4

putting in eq 2

=> - ( (2q - p)/4)²  +  (2q - p)/4   = q

=> - ( 4q² + p² - 4pq)  + 4(2q - p)  = 16q

=> -4q² - p² + 4pq + 8q - 4p = 16q

=> p² + 4q² - 4pq + 8q - 4p = 0