Question

Find the relation independent of y for the following equation
-2y^2-2y=p
-y^2+y=q

Answer 1

Answer:

-(q/2) - (p/4)² + (q/2) - (p/4) = q    .....(4)

Step-by-step explanation:

we are given that

-2y² - 2y = p   .............(1)

-y² + y = q    ...........(2)

Multiplying equation (2) by the 2 we get

-2y² + 2y = 2q     .............(3)

Subtracting equation (1) and (3) we get  

-4y = p - 2q

dividing by -4 we get

y = (q/2) - (p/4)

Putting the value of y = (q/2) - (p/4) in equation (2) we get

-(q/2) - (p/4)² + (q/2) - (p/4) = q    .....(4)

Equation (4) is the required equation independent from y because it does not involve y

Thus

-(q/2) - (p/4)² + (q/2) - (p/4) = q    .....(4)