Question

Find the relation independent of y of the equation y^2-2y+1=0

Answer 1

Answer:

y²-2y+1=0

y²-y-y+1=0

y(y-1) -1(y-1) =0

(y-1) (y-1) =0

y-1=0 and y-1=0

y=1 and y=1

Answer 2

Answer:

(Y-1) or, y = 1

Step-by-step explanation:

$y ^{2} - 2y + 1 = 0 \\{y}^{2} - 2 \times y \times 1 + {1}^{2} = 0 \\ (y - 1)^{2} = 0 \\ (y - 1) = 0 \\ y = 1$