Find the relationship between 4y2-15
Answers
Answer:
4y2-4y-15
Final result :
(2y - 5) • (2y + 3)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "y2" was replaced by "y^2".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(22y2 - 4y) - 15
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 4y2-4y-15
The first term is, 4y2 its coefficient is 4 .
The middle term is, -4y its coefficient is -4 .
The last term, "the constant", is -15
Step-1 : Multiply the coefficient of the first term by the constant 4 • -15 = -60
Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is -4 .
-60 + 1 = -59
-30 + 2 = -28
-20 + 3 = -17
-15 + 4 = -11
-12 + 5 = -7
-10 + 6 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 6
4y2 - 10y + 6y - 15
Step-4 : Add up the first 2 terms, pulling out like factors :
2y • (2y-5)
Add up the last 2 terms, pulling out common factors :
3 • (2y-5)
Step-5 : Add up the four terms of step 4 :
(2y+3) • (2y-5)
Which is the desired factorization
Final result :
(2y - 5) • (2y + 3)
Step-by-step explanation: