find the relationship between A and B so that the function is Defined by FX = x square - 1 if x less than or equal to 2 X + 3 is X greater than or equal to 2
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Given f(x)={
ax+1ifx≤3
bx+3ifx>3
Given function is continious at x=3
When lim
x→3
l(x)=l(3)
⇒3b+3=3a+1
⇒3a−3b=2
⇒a−b=
3
2
∴a−b=
3
2
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