find the relationship between the coefficient of X^ 2 - 2x - 8
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Answered by
0
Answer:
let,
P(x)=>x^2-2x-8=0
=>x^2-4x+2x-8=0
=>x(x-4)+2(x-4)=0
=>(x+2)(x-4)=0
Therefore,
x+2=0 or x-4=0
=>x= -2. =>x=4
Therefore, the zeros of the polynomials are -2 and 4
Sum of zeros= -2+4=2= -(-2)/1= -(coefficient of x)/coefficient of x^2
product of zeros= (-2)(4)= -8= -8/1= constant term/coefficient of x^2
Answered by
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Answer:
coefficient of X is -2
Step-by-step explanation:
because the equation is x^2-2x-8 and if there is a '-' or '+' sign the term is separated
so the term is -2x , and coefficient is the numeric value in a term beside the variable
.so hence numeric value is -2
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