Question

Find the relationship between x and y so that (x, y) is equidistant from (-3, 4) and (0, 3).​

Answer 1

Answer:

ANSWER

Since the point (x,y) is equidistant from the points (−3,4) and (0,3)

We find the distance between the points (x,y) and (0,3) that is :

D= (x−0) 2 +(y−3) 2 = x 2 +(y−3)

Now the distance between the points (x,y) and (−3,4) that is :

D= (x−(−3)) 2 +(y−4) 2 = (x+3) 2 +(y−4) 2

Now equate the distances as follows:

x 2+(y−3) 2 = (x+3) 2+(y−4) 2

Squaring both sides, we get

x 2+(y−3) 2 =(x+3) 2+(y−4) 2

⇒x 2 +y 2+9−6y=x 2+9+6x+y 2+16−8y

⇒−6y=6x+16−8y

⇒6x−2y+16=0

⇒3x−y+8=0