Question

find the relationship between x and y such that point p(x,y) is equidistant from the point A(2,-5) and B(-3,-7)​

Answer 1

Answer:

REFER IN ATTACHMENT

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Answer 2

Answer:

Step-by-step explanation:

The point p is equidisat to point AandB

so PA=PB

then we should find the distance between PA and PB

PA=(x2-x1)^2+(y2-y1)^2

    =(x-2)^2+(y+3)^2

    =x^2-4x+4+y^2+6y+9

    =x^2-4x+y^2+6y+13

PB=(x2-x1)^2+(y1-y2)^2

    =(x+5)^2+(y+7)^2

    =x^2+10x+25+y^2+14y+49

    =x^2+10x+y^2+14y+74

Now we should equate PA and PB

after solving we get the answer

-14x-8y+61