Physics, asked by rockyjoshuasingh, 10 months ago

Find the relative density of the substance whose density is 0.45g/cc

Answers

Answered by kampri
4

Explanation:

relative density =density of sub ÷density of water

both should have same unit

  1. 1 Lit=10^-9m^3
  2. 1Kg=10^-3 g
  3. so 0.45g/cc=0.45×10^6kg/m^3

relative density=0.45×10^6÷1000(dens.of water)

=450

Answered by NewGeneEinstein
5
  • Density of the substance=0.45g/cm^3

Convert to kg/m^3

\\ \sf\longmapsto 0.45\times 1000

\\ \sf\longmapsto 450kg/m^3

We know

\boxed{\sf Relative \:Density=\dfrac{Density\:of\:Substance}{Density\:of\:water\:at\:4°C}}

\\ \sf\longmapsto Relative\:Density=\dfrac{450}{1000}

\\ \sf\longmapsto Relative\:Density=0.45

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