Question

find the relative error in z if z= A4B1/3/CD3/2

Answer 1

Hello Friend..☃️☃️☃️


✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️

The answer of u r question is..✌️✌️

Find the relative error in z of z= A4B1/3/CD3/2..


Ans:✍️✍️✍️✍️✍️✍️✍️✍️

the error in z is...


∆Z=4∆A+1/3∆B+∆C+3/2∆D


✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️


Thank you..⭐️⭐️⭐️⭐️

Answer 2

Answer:

$\dfrac{\Delta z}{z}=4\dfrac{\Delta A}{A}+\frac{1}{3}\dfrac{\Delta B}{B}+\dfrac{\Delta C}{C}+\frac{3}{2}\dfrac{\Delta D}{D}$

Explanation:

Given that,

$z =\dfrac{A^{4}B^{\frac{1}{3}}}{CD^{\frac{3}{2}}}$

The relative error in z is defined as

Relative error = divided absolute value by the actual value

$\dfrac{\Delta z}{z}=4\dfrac{\Delta A}{A}+\frac{1}{3}\dfrac{\Delta B}{B}+\dfrac{\Delta C}{C}+\frac{3}{2}\dfrac{\Delta D}{D}$

Hence, This is the required solution.