find the remainde when f(x)=9xcube-3xsquare+14x-3 is divided by g(x) =(3x-1)
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By remainder theorem
Put g(x) =0
3x-1=0
x=1/3
So f(1/3)=remainder
=9(1/3)³-3(1/3)²+14(1/3)-3
=9/27-3/9+14/3-3
=(9-9+126-81)/27
=45/27
=5/3
Put g(x) =0
3x-1=0
x=1/3
So f(1/3)=remainder
=9(1/3)³-3(1/3)²+14(1/3)-3
=9/27-3/9+14/3-3
=(9-9+126-81)/27
=45/27
=5/3
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