Find the remainder 2^93 is divisible by 7
Answers
Answered by
1
2^93=(2^3)^31=8^31=(7+1)^31
now using binomial expansion u get
(31C0)7^31 +(31C1)7^30+...+(31C30)7 +(31C31)1
7c+1, so remainder is 1
now using binomial expansion u get
(31C0)7^31 +(31C1)7^30+...+(31C30)7 +(31C31)1
7c+1, so remainder is 1
Similar questions