Question

find the remainder -2y^6+3y^3-5y-2 divided by (y+2) and (y-2)

Answer 1

Answer:

By remainder theorem

(y+2=0) & (y-2=0)

therefore, y = -2 or y = 2

Now,

P(-2) = -2^(-2)^6 +3^(-2)^3 -5^(-2)-2

P(-2) = 24 - 18 -20

P(-2) = 24 - 38

P(-2) = -14

and,

P(2) = -2^(2)^6 +3^(2)^3 -5^(2)-2

P(2) = -24 + 18 + 20

P(2) = -24 + 38

P(2) = 14

Hence, 14 and -14 are the remainders.

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