Question

find the remainder f(x)=x^6-x^4-x²+1, g(x) = x -2​

Answer 1

Answer:

f(x) = x^6-x^4-x^2+1

g(x)= x-2

g(x)= 0

x-2= 0

x= 0+2

x= 2

Put the value of 'x' in f(x).

f(x)= x^6-x^4-x^2+1

f(2)= 2^6-2^4-2^2+1

= 64-16-4+1

= 65-20

= 45

Therefore, 45 is the remainder.