Question

find the remainder if p(x) = x³-3x²+3x-2 is divided by (x-2) by remainder theorem
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Answer 1

Answer:

p(x)= x³-3x²+3x-2                         x-2 = 0

p(2) = 2³-3 x 2²+3 x -2                 x=0+2=2

p(2) = 4-3 x 4+3 x -2                    so,  take p(2)

p(2) = 1 x 7 x -2

p(2) = -14

Step by- step explanation:

Hope it will help you ^_^