Question

find the remainder if x^3+5x-6x^2+1 is divided by (X+2)​

Answer 1

Answer:

$p(x) = {x}^{3} + 5x - 6 {x}^{2} + 1$

$p(x) = {x}^{3} - 6 {x}^{2} + 5x + 1$

Dividing the p(x) by (x+2),

$= \frac{ {x}^{3} - 6 {x}^{2} + 5x + 1 }{x + 2}$

$remainder = - 41$

$quotient = {x}^{2} - 8x + 21$

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