Question

Find the remainder if xcube+2xsquare-5x+6is divided by x+1

Answer 1

Answer:

$p(x) = x^{3} + 2 {x}^{2} - 5x + 6 \\ g(x) = x + 1$

by using remainder theorem

$x + 1 = 0 \\ x = - 1$

$p( - 1) = {( - 1)}^{3} + 2 {( - 1)}^{2} - 5( - 1) + 6 \\ p( - 1) = ( - 1) + 2 + 5 + 6 \\ p( - 1) = 12$

The remainder is 12 if divided by x+1

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