Question

Find the remainder in the following case, when f(x) is divided by g(x):
f(x) = 4x³ + 6x² - 2x/3 + 5/6
g(x) = 2 - 3x

[Answer with solution compulsory]​

Answer 1

Solution

f(x) = 4x³ + 6x² - 2x/3 + 5/6

according to the remainder theorem..

g(x) = 2 - 3x=0

=>X=2/3

now the remainder is.

f(2/3)=4(2/3)³ + 6(2/3)² - 2(2/3)/3 + 5/6

=(32/27)+(24/9)-(4/9)+(5/6)

=(229/54)

Answer 2

Answer:

Given :–

g(x) =0

2-3x=0

x=2/3

Putting this value in f(x), we get

f(x) =4x³+6x²-2x/3+5/6

f(2/3)=4(2/3)³+6(2/3)²-2(2/3)/3+5/6

f(2/3)=4*8/27+6*4/9-4/9+5/6

f(2/3)=32/27+24/9-4/9+5/6

f(2/3)=32/27+20/9+5/6

f(2/3)=229/54

So answer is 229/54.

HOPE IT WILL HELP YOU.