Question

find the remainder is same when the polynomial p(x)= x cube + 8x square +17x+ ax is divided by ( x+2) and (x+1) find the value of a​

Answer 1

p(x)=x³+8x²+17x+ax

p(-2)=(-2)³+8(-2)²+17(-2)+a(-2)

=-8+32-34-2a

=32-42-2a

=-10-2a...(i)

p(-1)=(-1)³+8(-1)²+17(-1)+a(-1)

=-1+8-17-a

=-10-a...(ii)

Now :

-10-a=-10-2a

-a+2a=-10+10

a=0