Math, asked by harpreetbedi, 1 year ago

find the remainder obtained on dividing 2x⁴-3x³-5x²+x+1by x-1/2​

Answers

Answered by Anonymous
7

\huge\mathcal\purple{Bonjour!!}

\huge\bold\pink{ANSWER:}

The answer is given in the attachment above...have a glimpse at it...

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Hope it helps...:-)

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Be Brainly..✌✌✌

Attachments:

Anonymous: Is it right dear?
Anonymous: Yep dear..
Anonymous: bye ....Have A great afternoon
Anonymous: how do you change color dear?
Anonymous: how can i do that?
Anonymous: like answer in pink color.
Anonymous: please tell me
Answered by Anonymous
12

Answer:

Hello Dear User__________

Here is Your Answer...!!

____________________

Step-by-step explanation:

Given \ p(x)=2x^{4}-3x^{3}-5x^{2}+1 \ and \ g(x)=x-\frac{1}{2}\\\\putting \ value \ of \ g(x) \ in \ p(x)\\\\p(\frac{1}{2})=2 \times(\frac{1}{2})^{4}-3(\frac{1}{2})^{3}-5(\frac{1}{2})^{2}+(\frac{1}{2})+ 1 \\\\p(\frac{1}{2})=\frac{1}{8}-\frac{3}{8}-\frac{5}{4}+\frac{1}{2}+1\\\\p(\frac{1}{2})=\frac{1-3-10+4+8}{8}\\\\p(\frac{1}{2})=\frac{13-13}{8}\\\\p(\frac{1}{2})= 0

Hope it is clear to you.


Anonymous: otherwise
Anonymous: your answer is correct
Anonymous: too
Anonymous: yaa you ahve missed one term
Anonymous: even I did a small mistake.... I thought it was 3x⁴
Anonymous: but... just few minutes ago.. I noticed that it was 3x³
Anonymous: Well... I have edited my answer...:-)
Anonymous: What term have I missed?
Anonymous: k... toodles dear...ttyl... have a pleasant afternoon
Anonymous: you too
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