Find the remainder obtained on dividing 3^97 by 10
Answers
Answered by
1
When the power of Its last digit
three is raised by
1 3
2 9
3 7
4 1
5 3
6 9
Observing this pattern it is clear that the last digits are repeating themselves after the interval of 4.
Now we need to know what is the last digit of 3^97
So,
97(mod 4)= 1
Therefore the Last digits is same as that of 3^1 i.e. 3
We know that the remainder of a number divided by 10 is equal to the last digit of the number.
Here last digit of the number is 3
Hence the required remainder is 3.
Please mark this solution as a brainliest answer and also follow me for more such detailed solutions in maths and physics.
Regards,
Gaurav kumar
three is raised by
1 3
2 9
3 7
4 1
5 3
6 9
Observing this pattern it is clear that the last digits are repeating themselves after the interval of 4.
Now we need to know what is the last digit of 3^97
So,
97(mod 4)= 1
Therefore the Last digits is same as that of 3^1 i.e. 3
We know that the remainder of a number divided by 10 is equal to the last digit of the number.
Here last digit of the number is 3
Hence the required remainder is 3.
Please mark this solution as a brainliest answer and also follow me for more such detailed solutions in maths and physics.
Regards,
Gaurav kumar
Similar questions