Find the remainder obtained on dividing p(x) = x^3 + 1 by x + 1. ( Please do it on a notebook and please elaborate each step -:)
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Given p(x)=x 3 +1 x+1 x 3+1 = x+1(x+1)(x 2 −x+1) =x 2 −x+1
Therefore, p(x) is divisible by x+1.
Hence, the remainder is zero.
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Step-by-step explanation:
$$\huge\bold{\purple{\fbox {\pink{\mathbb{ANSWER}}}}}$$
$$\bold{\longmapsto}$$ Given p(x)=x 3 +1 x+1 x 3+1 = x+1(x+1)(x 2 −x+1) =x 2 −x+1
$$\bold{\longmapsto}$$ Therefore, p(x) is divisible by x+1.
$$\bold{\longmapsto}$$ Hence, the remainder is zero.
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