Question

Find the remainder obtained on dividing p(x) = x^3 + 1 by x + 1. (x^3 read it as x cube)​

Answer 1

Step-by-step explanation:

p(x)=x³+1

$let \: consider \: the \: point \: x + 1 = 0$

$x = - 1$

$put \: \: this \: value \: in \: p(x)$

$p( - 1) = { - 1}^{3} + 1 = - 1 + 1 = 0$

$\: \: \: the \: remainder \: will \: be \: 0$