Question

find the remainder obtained on dividing p(x)=x^4+1 by x-1​

Answer 1

         

$The remainder obtained on dividing \ \ p(x)=x^4+1=0\ \ by \ (x-1)\ is \ \ p(1). \\ \\ \\ \therefore\ p(1)=1^4+1 \\ \\ \Rightarrow\ p(1)=1+1 \\ \\ \Rightarrow\ p(1)=\bold{2} \\ \\ \\ \therefore\ \bold{2}\ is the answer. \\ \\ \\ \\ Plz ask me if you've any doubts. \\ \\ \\ Thank you. :-))$