Question

Find the remainder obtained on dividing P(x)=x³+1 by x+1.​

Answer 1

Step-by-step explanation:

$\huge\red{\underline{\underline{\bf Question}}}$

P(x) = x³ + 1

find remainder when divided by x + 1

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$\huge { x + 1 = 0 }\\ \\ \huge{ x = - 1}$

$put \: x = - 1 \: in \: P(x) = > \\ \\ P(x) = {x}^{3} + 1 \\ \\ \implies P( - 1) = {( - 1)}^{3} + 1 \\ \\ \implies P( - 1) = - 1 + 1 \\ \\ \implies P ( - 1) = 0$

Here we got our remainder as zero

$</p><p>So, \: when \: {x}^{3}+ 1 \: is \: divided \: by \: x +1 \: \\ we'll \: get \: our \: remainder \: as \: \huge{zero. }$

Answer 2

$\bf\huge\underline{Answer}$

$\huge{\underline{\boxed{\sf Remainder \: - 0}}}$

$\bf\huge\underline{Solution :-}$

The remainder obtained when p(x) is divided by x + 1

At first, We'll find zero of the linear polynomial (x + 1)

=> x + 1 = 0

=> x = -1

Putting the value of 'x' :-

= (-1)³ + 1

= -1 + 1

= 0

Hence, The remainder is 0