Question

Find the remainder of the polynomial (3x^4+x^2-5) ÷(x+4)​

Answer 1

Dividend = 3x⁴-4x³-3x-1

Divisor = x - 1

Quotient = 3x³-x²-x-4

Remainder = -5

Step-by-step explanation:

Given (3x⁴-4x³-3x-1)÷(x-1)

Quotient : 3x³-x²-x-4

x-1) 3x⁴-4x³+0-3x-1

**** 3x⁴-3x³

______________________

*******-x³+0

******* -x³ + x²

______________________

*********** -x² -3x

********** -x² + x

______________________

*********** -4x - 1

************ -4x +4

______________________

******Remainder ( -5 )

Therefore,

Dividend = 3x⁴-4x³-3x-1

Divisor = x - 1

Quotient = 3x³-x²-x-4

Remainder = -5