Question

Find the remainder of the polynomial 7x cube +2x square +3x+5 when divided by x-1

Answer 1

Answer:

Remainder is 17

Step-by-step explanation:

$\rm Dividing\ \underbrace{7x^3 +2x^2 + 3x+5 }_{Dividend}\ by\ \underbrace{x-1 }_{Divisor}$

Step 1:

Divisor = 0

x-1=0

x=1

Step 2:

$\rm{Let}\ p(x)=7x^{3}+2x^{2}+3x+5$

[Putting x=1]

$p(1)=7(1)^{3}+2(1)^{2}+3(1)+5$

$=7(1)+2(1)+8$

$=7+2+8$

$=17$

∴ Remainder is 17