Question

Find the remainder on dividing 5y³ – 2y² – 7y + 1 by y.​

Answer 1

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Answer 2

Given :- Find the remainder on dividing 5y³ – 2y² – 7y + 1 by y. ?

Solution :-

dividing 5y³ – 2y² – 7y + 1 by long division method we get,

y ) 5y³ – 2y² – 7y + 1 ( 5y² - 2y - 7

-5y³

-2y²

-2y²

-7y

-7y

1

we get,

→ Quotient = 5y² - 2y - 7

→ Remainder = 1 (Ans.)

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. Find all the zeroes of the polynomial x4

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